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: <math>\left(\sqrt{x}\right)' = \left(x^{1\over 2}\right)' = {1 \over 2} x^{-{1\over 2}} = {1 \over 2 \sqrt{x}}, \qquad x > 0</math>
== Derivatet e funksioneve eksponenciale dhe logaritmike ==
:<math> \left(c^x\right)' = {c^x \ln c },\qquad c > 0</math>
:<math> \left(e^x\right)' = e^x</math>
:<math> \left( \log_c x\right)' = {1 \over x \ln c}, \qquad c > 0, c \ne 1</math>
:<math> \left( \ln x\right)' = {1 \over x}, \qquad x > 0</math>
:<math> \left( \ln |x|\right)' = {1 \over x}</math>
:<math> \left( x^x \right)' = x^x(1+\ln x)</math>
JANE BAZE PER TE MESUAR ANALIZEN MATEMATIKE
== Derivatet e funksioneve hiperbolike ==
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