Tabela e derivateve: Dallime mes rishikimesh

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Rreshti 71:
|<math> (\cot x)' = -\csc^2 x = { -1 \over \sin^2 x} \,</math>
|<math> (\arccot x)' = {-1 \over 1 + x^2} \,</math>
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== Derivatet e funksioneve hiperbolike ==
 
{| style="width:100%; background:transparent; margin-left:2em;"
|width=50%|<math>( \sinh x )'= \cosh x = \frac{e^x + e^{-x}}{2}</math>
|width=50%|<math>(\operatorname{arsinh}\,x)' = { 1 \over \sqrt{x^2 + 1}}</math>
|-
|<math>(\cosh x )'= \sinh x = \frac{e^x - e^{-x}}{2}</math>
|<math>(\operatorname{arcosh}\,x)' = { 1 \over \sqrt{x^2 - 1}}</math>
|-
|<math>(\tanh x )'= \operatorname{sech}^2\,x</math>
|<math>(\operatorname{artanh}\,x)' = { 1 \over 1 - x^2}</math>
|-
|<math>(\operatorname{sech}\,x)' = - \tanh x\,\operatorname{sech}\,x</math>
|<math>(\operatorname{arsech}\,x)' = {-1 \over x\sqrt{1 - x^2}}</math>
|-
|<math>(\operatorname{csch}\,x)' = -\,\operatorname{coth}\,x\,\operatorname{csch}\,x</math>
|<math>(\operatorname{arcsch}\,x)' = {-1 \over x\sqrt{1 + x^2}}</math>
|-
|<math>(\operatorname{coth}\,x )' = -\,\operatorname{csch}^2\,x</math>
|<math>(\operatorname{arcoth}\,x)' = { 1 \over 1 - x^2}</math>
|}